送交者: Amsel 于 2008-12-16, 14:03:07:
回答: N个(0,1)之间独立的随机数的和的演示 由 Amsel 于 2008-12-16, 13:10:31:
for count = 1:N prob_S =conv(prob_S,prob_A); disp([count,trapz(prob_s(count*mesh/2+mesh*0.5:end-1))]) plot(prob_S), hold onend
(trapz求积分有些误差)
加跟贴
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