total energy=rotation energy + translation energy


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送交者: gyro 于 2009-09-14, 11:15:13:

回答: is case 2)a pure rotation ? if so, 由 @ 于 2009-09-14, 11:03:25:

total energy at any height is fixed, the initial kinetic energy plus the potential energy.

rotation energy is zero in case 1), nonzero in case 2) because friction causes the ball to roll.

So at any position the translational velocity of case 1) is larger than that of case 2).




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